

GRE : Quantitative Comparison Problem
Y = 3X/4: X = 2Z/3 and Z = 20 Column A : Y Column B : 11 Since as per the information given, Z = 20 X = 2Z/3 = X = 2 x 20/3 = X = 40/3 Y = 3X/4 = Y = [3 x 40/3] / 4 = Y = 3 x [40/4x3] = Y = [3 x 40]/ 12 = Y = 120/12 = Y = 10. So, B is greater than A. So, the answer is B. This is the Quantitative Comparison Problem.Understand the basic mathematical principles behind this problem and other problems.
Go to The GREModel Questions Index
From Quantitative Comparison Problem7 to HOME PAG

Follow These Links!


