GRE : Quantitative Comparison Problem
This is the Quantitative Comparison Problem-9.Understand the basic mathematical principles behind this problem and other problems.
In a history class that consisted of 30 students, the number of seniors was 3 more than twice the number of juniors, and 3/10 of the students were neither juniors nor seniors.
Column A : The number of juniors in the class
Column B : 6
The number who were neither juniors nor seniors was 30 X 3/10
= 30 x 3/10
= 3 x 3
SO, the total number of juniors and the seniors is 30 – 9 = 21.
If the number of juniors was x
, it is given that the number if seniors was (2x + 3).
SO, (2x + 3) + x = 21
= 3x + 3 = 21
= 3x = 21 – 3
= 3x = 18
= x = 6
So, the number of juniors in the class is 6.
As per this information, A = B.
So, C is the answer.
This is the Quantitative Comparison Problem. Understand the basic mathematical principles behind this problem and other problems.
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