

GRE : Quantitative Comparison Problem
In a history class that consisted of 30 students, the number of seniors was 3 more than twice the number of juniors, and 3/10 of the students were neither juniors nor seniors. Column A : The number of juniors in the class Column B : 6 The number who were neither juniors nor seniors was 30 X 3/10 = 30 x 3/10 = 3 x 3 = 9 SO, the total number of juniors and the seniors is 30 – 9 = 21. If the number of juniors was x, it is given that the number if seniors was (2x + 3). SO, (2x + 3) + x = 21 = 3x + 3 = 21 = 3x = 21 – 3 = 3x = 18 = x = 6 So, the number of juniors in the class is 6. As per this information, A = B. So, C is the answer. This is the Quantitative Comparison Problem. Understand the basic mathematical principles behind this problem and other problems.
Go to The GREModel Questions Index
From Quantitative Comparison Problem9 to HOME PAG

Follow These Links!


